Answer:
[tex]|\vec{F}| =48.60\ N[/tex]
Explanation:
given,
Current in the power line = I = 5500 A
earth's magnetic field = 60.0 μT
inclination downward = 67°
Length = 160 m
magnetic force = ?
[tex]\vec{F} = I (\vec{L}\times \vec{B})[/tex]
[tex]|\vec{F}| = I |(\vec{L}\times \vec{B})|[/tex]
[tex]|\vec{F}| =I LB sin \theta [/tex]
[tex]|\vec{F}| = 5500 \times 160 \times 60 \times 10^{-6}\times sin 67^0[/tex]
[tex]|\vec{F}| =48.60\ N[/tex]
According to the right hand rule the direction of the force is perpendicular to the plane of the length and the magnetic field so, it is to west.
