Answer:
The width of the sandbox is [tex]42\frac{2}{3} \ ft[/tex].
Step-by-step explanation:
Given,
Area of the sandbox = [tex]10\frac{2}{3}=\frac{32}{3}\ ft^2[/tex]
Length = [tex]\frac{1}{4}\ ft[/tex]
Solution,
Let the width of the sandbox be 'w'.
Since the sandbox is in shape of rectangle.
So we use the formula of area of rectangle.
[tex]Area = Length\times Width[/tex]
On substituting the given values, we get;
[tex]\frac{1}{4}\times w=\frac{32}{3}\\[/tex]
By cross multiplication method, we get;
[tex]w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft[/tex]
Hence The width of the sandbox is [tex]42\frac{2}{3} \ ft[/tex].
