Answer:
Noise level will be -18.2 watt
So option (b) will be correct answer
Explanation:
We have given sound intensity [tex]I=1.5\times 10^{-14}w/m^2[/tex]
And threshold intensity [tex]I_0=\times 10^{-12}w/m^2[/tex] ( in question it is given as [tex]10^{12}w/m^2[/tex] but its standard value is [tex]10^{-12}w/m^2[/tex] )
Now noise level [tex]=10log\frac{I}{I_0}=10log\frac{1.5\times 10^{-14}}{10^{-12}}=10log0.015-18.23[/tex]
So the noise level will be -18.2
So option (b) will be correct answer
