Answer:
The ratio of Tan B is
[tex]\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}[/tex]
OR
[tex]\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}[/tex]
Step-by-step explanation:
In Right Angle Triangle ABC
angle C = 90°
AB = Ramp = 17 feet
BC =Horizontal distance = 15 feet
AC = Height from floor = 8 feet
To Find:
Ratio of Tan B = ?
Solution:
In Right Angle Triangle ABC By Tangent Identity we have
[tex]\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}[/tex]
Substituting the given values we get
[tex]\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}[/tex]
OR
[tex]\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}[/tex]
