Answer:
[tex]-3m {s}^{-2} [/tex]
Explanation:
The initial velocity, u, of the car=15m/s
The final velocity, v, of the car =0m/s
Time, t, taken for the car to come to a stop=5s
Acceleration is calculated by,
[tex] a= \frac{v - u}{t} [/tex]
By substitution,
[tex]a= \frac{0- 15}{5}[/tex]
[tex]a= \frac{- 15}{5} [/tex]
[tex]a = -3 {ms}^{ - 2} [/tex]
The negative sign implies that the car has decelerated.
