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A(n) 59 kg astronaut becomes separated from
the shuttle, while on a spacewalk. She finds
herself 63.2 m away from the shuttle and moving with zero speed relative to the shuttle. She
has a(n) 0.695 kg camera in her hand and decides to get back to the shuttle by throwing
the camera at a speed of 12 m/s in the direction away from the shuttle.
How long will it take for her to reach the
shuttle? Answer in minutes.
1. 10.06 min
2. 9.687 min
3. 8.569 min
4. 8.197 min
5. 7.452 min
6. 7.824 min
7. 10.43 min
8. 8.942 min

Respuesta :

MathPhys

Answer:

5. 7.452 min

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

0 = (0.695 kg) (-12 m/s) + (59 kg) v

v = 0.1414 m/s

She is 63.2 m away, so the time it takes to reach the shuttle is:

t = 63.2 m / 0.1414 m/s

t = 447.1 s

t = 7.452 min

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