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A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s 2 . What is the magnitude of the mechanical energy lost due to friction acting on the runner?

Respuesta :

Answer:

[tex]147.653J = W_f[/tex]

Explanation:

We know that:

[tex]E_i - E_f = W_f[/tex]

where [tex]E_i[/tex] is the initial energy, [tex]E_f[/tex] is the final energy and [tex]W_f[/tex] is the energy lost due to friction.

so:

[tex]\frac{1}{2}MV^2-0 = W_f[/tex]

Where M is the mass and V is the velocity of the runner, so:

[tex]\frac{1}{2}(68.2kg)(4.33m/s)^2 = W_f[/tex]

[tex]147.653J = W_f[/tex]

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