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During a physical examination, Joe learns that his resting tidal volume is 500 ml; his average resting respiratory rate is 12 breaths per minute; his total lung capacity is 6000 ml; and his anatomic dead space is 150 ml. Joe's resting alveolar ventilation is
A. 72.0 L/minB. 6.0 L/minC. 4.2 L/minD. 1.8 L/minE. 0.5 L/min

Respuesta :

Answer:

Option C

Explanation:

Given -

Tidal volume is equal to [tex]500[/tex] ml

Average resting respiratory rate is equal to [tex]12[/tex] breathes per minute

Anatomic dead space volume is equal to  [tex]150[/tex] ml

As we know -

Resting alveolar ventilation [tex]= Rate * (TD - ADS)[/tex]

Where TD represents tidal volume and ADS represents Anatomic dead space volume

Substituting the given values in above equation, we get -

[tex]12 (500-150)\\12 * 350 \\= 4200\\= 4.2[/tex] L/min

Hence, option C is correct

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