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Suppose that X1,...,Xn form a random sample from the normal distribution with unknown mean μ and known variance 1. Suppose also that μ0 is a certain specified number, and that the following hypotheses are to be tested: H0: μ = μ0, H1: μ = μ0. Finally, suppose that the sample size n is 25, and consider a test procedure such that H0 is to be rejected if |Xn − μ0| ≥ c. Determine the value of c such that the size of the test will be 0.05.

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Answer:

c=0.392

Step-by-step explanation:

Given that X1,...,Xn form a random sample from the normal distribution with unknown mean μ and known variance 1.

Suppose also that μ0 is a certain specified number, and that the following hypotheses are to be tested:

[tex]H0: \mu = \mu_0 Vs  H_1: \mu \neq \mu_0[/tex]

This is two tailed test.

Alpha =0.05

Sample size = 25

we reject null hypothesis if [tex]\frac{|x_n - \mu_0}|{\frac{1}{\sqrt{25} } } \geq 1.96[/tex]

Or [tex]|x_n - \mu_0|\geq 1.96/5 = 0.392[/tex]

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