Answer:
[tex]v_f = 17.15 m/s[/tex]
[tex]t = 9.43 s[/tex]
Explanation:
Initial speed of the car is given as
[tex]v_i = 3 m/s[/tex]
acceleration of the car
[tex]a = 1.5 m/s^2[/tex]
distance moved by the car
[tex]d = 95 m[/tex]
now we can use kinematics to find the final speed of the car
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]v_f^2 - 3^2 = 2(1.5)(95)[/tex]
[tex]v_f^2 = 294 [/tex]
[tex]v_f = 17.15 m/s[/tex]
Now the time taken to reach this speed is given as
[tex]v_f = v_i + at[/tex]
[tex]17.15 = 3 + 1.5 t[/tex]
[tex]t = 9.43 s[/tex]
