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A baseball is thrown from the roof of 21.6 m tall building with an initial velocity of magnitude 12.0 m/s and directed at an angle of 48.2 above the horizontal. What is the speed of the ball just before it strikes the ground? Use energy methods and ignore air resistance.

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akujorclinton

Answer:

23.8m/S

Explanation:

Given data:  h1 = 21.6m  v1 = 10.3 m/s

Angle = 48.2o

g = 9.8 m/s2

Speed of ball just before it strikes the ground.  

Using conservation of energy:

E1 = E2

Where, E1 = Initial energy,           E2 = Final energy

So, K1 + U1 = K2 + U2

Where, K1 = initial kinetic energy,   U1 = Initial potential energy

K2 = Final kinetic energy,      U2 = Final potential energy

recall K =1/2MV[tex]x^{2}[/tex]

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