A twin-engine plane flies 380 mi in the same amount of time it takes a single-engine plane to fly 220 mi. The rate of the twin-engine plane is 80 mph faster than the rate of the single-engine plane. Find the rate of the single-engine plane.

Respuesta :

Answer:

The rate of the single engine plane is 110 mph.

Step-by-step explanation:

Let the rate of single engine plane be n mph,

And the rate of twin engine plane will be n + 80 mph.

We know that, distance = speed x time.

Then, for twin engine plane

380 = (n + 80) x time taken

[tex]\text{{time taken}} = \frac{380}{n+80}[/tex]

And, for single engine plane

220 = n x time taken

[tex]\text{{time taken}} = \frac{220}{n}[/tex]

It is given that, both planes took same time.

Then, [tex]\frac{380}{n +80} = \frac{220}{n}[/tex]

380n = 220n + 220 x 80  

380n – 220n = 17600  

160n = 17600

[tex]n =\frac{17600}{160}[/tex]

  n = 110

Hence, the rate of the single engine plane is 110 mph.