Answer:
(C) second order
Explanation:
Let's consider the following reaction.
2X --> Y + Z
The rate law is:
r = k . [A]ˣ
where,
r is the rate of the reaction
k is the rate constant
x is the reaction order of A
Let's assume x = 2. If the concentration of A is doubled, the new rate r₁ is:
r₁ = k . [2A]² = 4 . k . [A]² = 4 . r
The new rate r₁ is 4 times r when [A] is doubled. This happens when x = 2, that is, it is a second reaction order.
