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A late traveler rushes to catch a plane, pulling asuitcase with a force directed 30 degrees above the horizontal. Ifthe horizontal component of the force on the suitcase is 60.6 N,what is the force exerted on the handle? (Explain, please,how you did it)
a) 53 N
b) 70 N (?)
c) 95.6 N
d) 65.2 N

Respuesta :

Answer:

Force will be 70 N so option (b) is correct option

Explanation:

We have given horizontal component of the force

[tex]F_x=60.6N[/tex]

Angle [tex]\Theta =30^{\circ}[/tex]

We have to find the net force

We know that horizontal force is given by [tex]F_X=Fcos\Theta[/tex]

So force F [tex]=\frac{60.6}{cos30}=\frac{60.6}{0.866}=69.97= 70 N[/tex]

So option (b) is correct option

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