Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :
[tex]v=u+at[/tex]
In case of crash the final speed of the driver is, v = 0
[tex]0=u+at[/tex]
[tex]-u=at[/tex]
[tex]-u=-50\times 9.8\times 30\times 10^{-3}[/tex]
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.