Respuesta :
Answer:
The program to this question can be given as:
Program:
#include<cstdio> //include header file.
#include<vector>
using namespace std;
int maxSum(vector <int>a); //function declaration
int maxSum(vector <int>a) //function definition
{
int i, n=a.size(),max_fast = 0,max_end= 0; //declare variable
for(i = 0; i < n; i++) //for loop
{
max_end = max_end+ a[i]; //add value in max_end
if(max_end < 0) //check value
{
max_end = 0;
}
if(max_fast < max_end)
{
max_fast = max_end; //assign value to max_fast
}
}
return max_fast; //return value.
}
int main() //main function.
{
vector<int> a;
//insert values.
a.push_back(-2);
a.push_back(-3);
a.push_back(4);
a.push_back(-1);
a.push_back(-2);
a.push_back(1);
a.push_back(5);
a.push_back(-3);
int max_sum; //define variable
max_sum = maxSum(a); //calling function.
printf("Maximum contiguous sum is %d\n", max_sum); //print value.
return 0;
}
Output:
Maximum contiguous sum is: 7
Explanation:
In the above program firstly we include header files. the we declare the function that name is already given in the question. In that function we declare variable and assign a value to variable. Then we declare the loop that is used for add the value of max_end. In this loop we use the multiple if statements in first if block we check that the value of max_end less then 0. When the condition is true max_end =0.In second if block we check that max_fast value is less then max_end. If it is true so we assign max_fast=max_end and return max_fast value. In the last we declare the main function .In this we assign the value in array and pass the array into the function and call the function.The ma_sum variable hold the return values of the function and in the last we print max_sum value.
