Respuesta :
Answer: [tex]N_2O[/tex] has the highest mass percent of nitrogen.
Explanation:
To calculate the percentage composition of a nitrogen in a compound, we use the equation:
[tex]\%\text{ composition of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Mass of compound}}\times 100[/tex] .......(1)
Molar mass of nitrogen = 14 g/mol
- For NO:
Mass of NO = 30.01 g/mol
Mass of nitrogen = [tex][1\times 14]=14g/mol[/tex]
Putting values in equation 1, we get:
[tex]\%\text{ composition of nitrogen}=\frac{14g}[30.01}\times 100\\\\\%\text{ composition of nitrogen}=46.65\%[/tex]
The mass percent of nitrogen in given compound is 46.65 %
- For [tex]NO_2[/tex] :
Mass of [tex]NO_2[/tex] = 46.01 g/mol
Mass of nitrogen = [tex][1\times 14]=14g/mol[/tex]
Putting values in equation 1, we get:
[tex]\%\text{ composition of nitrogen}=\frac{14g}[46.01}\times 100\\\\\%\text{ composition of nitrogen}=30.43\%[/tex]
The mass percent of nitrogen in given compound is 30.43 %
- For [tex]N_2O[/tex] :
Mass of [tex]N_2O[/tex] = 44.01 g/mol
Mass of nitrogen = [tex][2\times 14]=28g/mol[/tex]
Putting values in equation 1, we get:
[tex]\%\text{ composition of nitrogen}=\frac{28g}[44.01}\times 100\\\\\%\text{ composition of nitrogen}=63.62\%[/tex]
The mass percent of nitrogen in given compound is 63.62 %
- For [tex]N_2O_4[/tex] :
Mass of [tex]N_2O_4[/tex] = 92.01 g/mol
Mass of nitrogen = [tex][2\times 14]=28g/mol[/tex]
Putting values in equation 1, we get:
[tex]\%\text{ composition of nitrogen}=\frac{28g}[92.01}\times 100\\\\\%\text{ composition of nitrogen}=30.43\%[/tex]
The mass percent of nitrogen in given compound is 30.43 %
Hence, [tex]N_2O[/tex] has the highest mass percent of nitrogen.