Answer:
A baseball player hit 73 home runs in a season.
Of the 73 home runs, 25 went to right field, 25 went to right center field, 8 went to center field, 10 went to left center field, and 5 went to left field.
(a) the probability that a randomly selected home run was hit to left center field = [tex]\frac{10}{73}=0.1369[/tex] = 13.69%
(B) Since the probability of an unusual event is 0, it was possible for this player to hit a home run to left center field.
