Respuesta :
Hello,
[tex] \int\limits^h_0 {\frac{1}{2\pi} * e^{\frac{-(x-68)^2}{2}} dx}=0.4985 [/tex]
==>h=3*4=12
[68-12, 68+12] is the interval
Answer A
[tex] \int\limits^h_0 {\frac{1}{2\pi} * e^{\frac{-(x-68)^2}{2}} dx}=0.4985 [/tex]
==>h=3*4=12
[68-12, 68+12] is the interval
Answer A