The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = 3/2 . What is the value of b?

the axis of symmety is the x value of the vertex

to find the x value of the vertex of ax^2+bx+c=0
x value=-b/2a

3x^2+bx+4=0
3/2=vertex

-b/2(3)=3/2
-b/6=3/2
times 6
-b=18/2
-b=9
times -1
b=-9

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-07-04T10:09:56+02:00

The axis of symmetry for the graph of the function f(x) = 3x2 + bx + 4 is x = 3/2. The value of b is -9.

What is a function?

The function is a type of relation, or rule, that maps one input to a specific single output.

The axis of symmetry for the graph of the function

f(x) = 3x2 + bx + 4

x = 3/2 .

In order to find the b value of the vertex of ax^2 + bx + c=0

x = -b/2a

3x^2+bx+4 = 0

Given;

3/2 = vertex

-b/2(3) = 3/2

-b/6 = 3/2

-b = 18/2

-b = 9

b=-9

Thus, The value of b is -9.

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