Answer: Probability that the entire batch will be accepted is 0.658.
Yes, this suggests entire batch of good CDs as it is the only condition to get accepted.
Step-by-step explanation:
Since we have given that
Number of CDs = 507
Number of defective = 65
Since the entire batch will be accepted.
So, the probability of success is p = [tex]\dfrac{507-65}{507}=\dfrac{442}{507}=0.87[/tex]
and the probability of failure is q = [tex]\dfrac{65}{507}=0.128[/tex]
Number of CDs selected = 3
So, Probability that the entire batch will be accepted is given by
[tex]P(X=3)=^3C_3(0.87)^3\\\\P(X=3)=0.658[/tex]
Hence, Probability that the entire batch will be accepted is 0.658.
Yes, this suggests entire batch of good CDs as it is the only condition to get accepted.