Answer:
a) t = 2.64s
b) Vf = -28.7m/s
Explanation:
If the balloon is descending, the velocity is -2.3m/s. So the equation to describe the postion of the falling camera is:
[tex]Y = Vo*t - \frac{g*t^{2}}{2}[/tex]
[tex]-41 = -2.3*t - \frac{10*t^{2}}{2}[/tex] Solving for t, we get:
t1 = -3.1s and t2 = 2.64s We discard the negative time and use the positive one.
The velocity of the camera will be:
Vf = Vo - g*t = -2.3 - 10*2.64 = -28.7m/s
