autumnmaise
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Sara leaves home at 7am traveling at a rate of 45 mi/h. her son discovers that she has forgotten her briefcase and starts out to catch up with her. her son leaves at 7:30 am traveling at a rate of 55 mi/h. At what time will he over take his mother?

Respuesta :

Sara 45 mph
Son 55 mph
Sara 07:00
Son 07:30
Difference in time= 00:30 => 0.50 hours
Sara will have covered 22.50 miles Son starts

catch up distance= 22.50 miles
catch up speed = 55 -45
catch up speed = 10 mph
Catchup time = catchup distance/catch up speed
catch up time= 2.25
catch up time= 2.25 hours
They will meet at 9:55 am mph 

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