Answer:
Step-by-step explanation:
Given
Shopper pushes a cart 50 m south down then turns 90 ^{\circ} west and moves 23 m.
he then makes [tex]90^{\circ}[/tex] turn and moves 14 m
(a)Largest possible displacement is when he turns towards south
Net displacement[tex]=\sqrt{64^2+23^2}=68.0 m[/tex]
(b)Smallest displacement when he turns towards north
[tex]=\sqrt{36^2+23^2}[/tex]
[tex]=\sqrt{1825}=42.72 m[/tex]
