Answer:
40 J-s
Explanation:
Given:
mass of the particle, m=0.1 kg
Acceleration of the particle, a = 10 m/s²
Time interval, ΔT = 2 - 0 = 2 seconds
Since the particle is initially at rest,
therefore the initial speed u = 0 m/s
The action, s is calculated as :
s = Force × distance × time interval
now,
from the Newton's equation of motion, we have
[tex]S = ut+\frac{1}{2}at^2[/tex]
where, S is the distance traveled after 2 seconds
on substituting the values, we have
[tex]S = 0\times2+\frac{1}{2}\times10\times2^2[/tex]
or
S = 20 m
also,
Force = mass × acceleration
thus,
Force = 0.1 × 10 = 1 N
on substituting the values, in the formula for the action, we get
s = 1 × 20 × 2
or
s = 40 J-s
