Consider an air parcel at latitude = 18◦N, moving northward (conserving absolute vorticity), with initial relative vorticity = 5.8 × 10−5 s −1 . Please calculate the relative vorticity of the air parcel when it reaches 50◦N.

Question

contestada

Respuesta :

DeniceSandidge DeniceSandidge · Answer 1 · 2019-08-26T11:15:10+02:00

Answer:

relative vorticity is -0.868 × [tex]10^{-5}[/tex] s-1

Explanation:

given data

air parcel at latitude = 18◦N

relative vorticity = 5.8 × 10^−5 s−1

to find out

relative vorticity

solution

we will apply here conservation of vorticity that is

ζ + f = constant

we know ζ initial = 2Ωsin(5π/18)

and f initial = 5.8 × [tex]10^{-5}[/tex]

and f final = 2Ωsin(π/18)

and here angular frequency Ω = 0.7272 × [tex]10^{-4}[/tex] s-1

its mean

ζ initial - ζ final = f final - f initial

so

ζ final = ζ initial - f final + f initial

ζ final = - 2Ωsin(5π/18) + ( 2Ωsin(π/18) + 5.8 × [tex]10^{-5}[/tex] )

ζ final = - 2(0.7272 × [tex]10^{-4}[/tex]) sin(5π/18) + ( 2(0.7272 × [tex]10^{-4}[/tex])sin(π/18) + 5.8 × [tex]10^{-5}[/tex] )

ζ final = -0.868 × [tex]10^{-5}[/tex] s-1

so relative vorticity is -0.868 × [tex]10^{-5}[/tex] s-1