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Determine the equation of motion of a point mass m attached to a coiled spring with spring constant k, initially displaced a distance x, from equilibrium, and released with velocity V, subject to no damping or other external forces. 1. m= 10kg , k = 1000/m, x, = 1m., V, = 0

Respuesta :

Answer:

Explanation:

Angular velocity w = [tex]\sqrt{\frac{m}{k} }[/tex]

m = 10 ;  k = 1000N  / m  

Putting these values we get

w = 0.1

Amplitude  A  = 1 m  

So equation of  S H M is

x = A cos ( wt )

Velocity dx / dt = Aw sin wt  when t = 0 , velocity = 0 (given )

The equation for motion is

x = 1 x cos ( 0.1 t )

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