Explanation:
It is given that,
Current in wire 1, I₁ = 10 A
Current in wire 2, I₂ = 20 A
Distance between wires, d = 10 cm = 0.1 m
Force per unit length is given by :
[tex]\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}[/tex]
[tex]\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 10\times 20}{2\pi \times 0.1}[/tex]
[tex]\dfrac{F}{l}=0.0004\ N/m[/tex]
[tex]\dfrac{F}{l}=4\times 10^{-4}\ N/m[/tex]
So, the magnetic force acting per unit length of the wires [tex]4\times 10^{-4}\ N/m[/tex]. Since, the current is in same direction. So, the force is attractive in nature.
