Answer:
Bore = 7 cm
stroke = 6.36 cm
compression ratio = 10.007
Explanation:
Given data:
Cubic capacity of the engine, V = 245 cc
Clearance volume, v = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
V = [tex]\frac{\pi}{4}D^2L[/tex]
or
V = [tex]\frac{\pi}{4}\frac{D^3}{1.1}[/tex]
on substituting the values, we have
245 = [tex]\frac{\pi}{4}\frac{D^3}{1.1}[/tex]
or
D = 7.00 cm
Now,
we have
D/L = 1.1
thus,
L = D/1.1
L = 7/1.1
or
L= 6.36 cm
Now,
the compression ratio is given as:
[tex]\textup{compression ratio}=\frac{V+v}{v}[/tex]
on substituting the values, we get
[tex]\textup{compression ratio}=\frac{245+27.2}{27.2}[/tex]
or
Compression ratio = 10.007
