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A 20.0 F capacitor initially charged to 30.0 uC is discharged through a 3.00 k resistor. How long does it take to reduce the capacitor's charge to 15.0 C? Express your answer with the appropriate units. ?

Respuesta :

Answer:

t = 0.04159 s

Explanation:

when a capacitor and resister are connected in series. charge on its plates decreases exponentially

[tex]q = qo * e^{\frac{-t}{RC}}[/tex]

where,

CHARGE q  =15.0 C

INITIAL CHARGE q_0 = 30.0 uc

Resistor R = 20.0 F

capacitor C  = 3.00

[tex]15 = 30* e^{\frac{- t}{(20* 10^{-6} * 3* 1000)}[/tex]

t = 0.04159 s

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