Answer:
58.0 m/s
Explanation:
We can solve the problem by using the following SUVAT equation:
[tex]v^2 = u^2 +2as[/tex]
where
v is the final velocity of the roller coaster
u = 13 m/s is the initial velocity
a = 4.0 m/s^2 is the acceleration
s = 400 m is the displacement
Substituting and solving for v, we find
[tex]v=\sqrt{u^2 +2as}=\sqrt{(13)^2 +2(4)(400)}=58.0 m/s[/tex]
