Answer:
Wavelength, [tex]\lambda=1.148\times 10^{-7}\ m[/tex]
Explanation:
It is given that,
Two point sources (pixels) of monochromatic radiation can be resolved as close as 0.3 cm apart, x = 0.3 cm = 0.003 m
Diameter of lens, d = 7 cm = 0.07 m
Distance from the view line, D = 1500 m
We need to find the wavelength of the radiation. The formula for resolving power of Rayleigh criterion is given by :
[tex]d=\dfrac{1.22\lambda D}{x}[/tex]
[tex]\lambda=\dfrac{xd}{1.22D}[/tex]
[tex]\lambda=\dfrac{0.003\times 0.07}{1.22\times 1500}[/tex]
[tex]\lambda=1.148\times 10^{-7}\ m[/tex]
So, the wavelength of the radiation is [tex]1.148\times 10^{-7}\ m[/tex]. Hence, this is the required solution.
