Answer:429.8 KW
Explanation:
carbon dioxide Inlet temperature [tex]300K [/tex] and pressure 100 KPa
At given Temperature and presssure [tex]c_p_1=0.846 kJ/kg-k[/tex]
Flow rate [tex]\dot{m} =1.5 kg/s[/tex]
Steam Outlet temperature and Pressure is [tex]500K[/tex] and pressure is 600 KPa
[tex]c_p_2=1.014 kJ/kg-k[/tex]
Heat loss 50 KW
Applying Steady Flow Energy Equation
[tex]\dot{m}\left ( h_1+\frac{v_1^2}{2}+z_1 \right )+\dot{Q}=\dot{m}\left ( h_2+\frac{v_2^2}{2}+z_2 \right )+\dot{W}[/tex]
Neglecting Kinetic and Potential Energy changes
[tex]\dot{m}h_1+\dot{Q}=\dot{m}h_2+\dot{W}[/tex]
[tex]\dot{W}=\dot{m}\left ( c_p_1T_1-c_p_2T_2\right )+\dot{Q}[/tex]
[tex]\dot{W}=1.5\left ( 0.846\times 300-1.014\times 500\right )-50[/tex]
[tex]\dot{W}=429.8 KW[/tex]
Negative sign indicates work is being done on the system.
