Respuesta :
Answer:
[tex]3.815\times 10^{-8}j/sec[/tex]
Explanation:
Intensity due to spherical source of power is given by [tex]I=\frac{P}{4\pi r^2}[/tex]
Where P is the power of the source and r is the distance of the source
So intensity [tex]I=\frac{P}{4\pi r^2}=\frac{29}{4\pi \times 55^2}=7.63\times 10^{-4}[/tex] [tex]w/m^2[/tex]
Now the energy impinges on microphones per second [tex]P=I\times A[/tex] where I is the intensity and A is the area
Area is given as 0.5 [tex]cm^2[/tex]=[tex]0.5\times 10^{-4}m^2[/tex]
So power [tex]P=7.63\times 10^{-4}\times 0.5\times 10^{-4}=3.815\times 10^{-8}j/sec[/tex]
Sound energy/power is the product of the intensity and the area.
The sound energy impinges on the microphone each second is [tex]3.81\times10^{-6} \rm J/s[/tex].
What is sound energy?
Sound energy is the form of energy, produces when the object is vibrates.
Sound energy/power is the product of the intensity and the area. It can be given as,
[tex]P=I\times A[/tex]
Here [tex]P[/tex] is the sound power, [tex]I[/tex] is the intensity and [tex]A[/tex] is the area.
Given information-
A concert loudspeaker suspended high off the ground emits 29.0 W sound power.
The area of the microphone is 0.500 cm squared.
The distance of the specked and the microphone is 55 m.
Thus the sound energy impinges on the microphone each second can be given as,
[tex]P=I_L\times A_m[/tex]
Here, [tex]L[/tex] represents the loud speakers and [tex]m[/tex] represents the microphone.
Rewrite the above equation as,
[tex]P=\dfrac{P_L}{A_L} \times A_m\\P=\dfrac{29}{4\pi \times55^2} \times 0.005\\P=3.81\times10^{-6}[/tex]
Hence the sound energy impinges on the microphone each second is [tex]3.81\times10^{-6} \rm J/s[/tex].
Learn more about the sound energy here;
https://brainly.com/question/733324
