Respuesta :
Answer:
The average intensity of this beam and the distance are 631.4 w/m² and 2.86 cm.
Explanation:
Given that,
Power = 0.60 mW
Diameter = 1.1 mm
(A). We need to calculate the average intensity of this beam
Using formula of intensity
[tex]I=\dfrac{P}{A}[/tex]
Put the value into the formula
[tex]I=\dfrac{0.60\times10^{-3}}{\dfrac{\pi(1.1\times10^{-3})^2}{4}}[/tex]
[tex]I=631.4\ W/m^2[/tex]
(B). We need to calculate the distance
Given that,
Power = 130 W
5% of 130 W is 6.5 w
Using formula of intensity
[tex]I=\dfrac{P}{A}[/tex]
Put the value into the formula
[tex]631.4=\dfrac{6.5}{4\pi (r)^2}[/tex]
[tex]r^2=\dfrac{6.5}{4\pi\times631.4}[/tex]
[tex]r=\sqrt{0.000819}[/tex]
[tex]r =0.0286\ m=2.86\ cm[/tex]
The distance is 2.86 cm.
Hence, The average intensity of this beam and the distance are 631.4 w/m² and 2.86 cm.
