Answer:
[tex]\frac{91}{216}[/tex]
Step-by-step explanation:
1. you know that a dice has 6 sides, and 3 appears once on this dice...
if you roll the dice once, the probability that 3 will happen is [tex]\frac{1}{6}[/tex]
2. now solving the probability that a 3 will not occur... (this is so we can solve this problem "backwards")
[tex]\frac{5}{6} * \frac{5}{6} * \frac{5}{6}[/tex] [tex]=\frac{125}{216}[/tex]
- [tex]216[/tex] is the total number of possible rolls
- [tex]125[/tex] is the possible rolls that are not 3
3. now that we know the total and the probability that a 3 will not occur...
we can now solve then a 3 will occur!
[tex]216 - 125 = 91[/tex]
[tex]\frac{91}{216}[/tex] is the probability the 3 will be rolled!
:D
