Respuesta :
Answer : The mass of copper produced is, [tex]1.20\text{ metric ton}[/tex]
Explanation : Given,
Mass of bornite [tex]Cu_3FeS_3[/tex] = [tex]2.50\text{ metric ton}=2.50\times 10^6g[/tex]
conversion used : [tex]1\text{ metric ton}=10^6g[/tex]
Molar mass of [tex]Cu_3FeS_3[/tex] = 342.678 g/mole
First we have to calculate the moles of [tex]Cu_3FeS_3[/tex].
[tex]\text{Moles of }Cu_3FeS_3=\frac{\text{Mass of }Cu_3FeS_3}{\text{Molar mass of }Cu_3FeS_3}=\frac{2.50\times 10^6g}{342.678g/mole}=7295.48mole[/tex]
Now we have to calculate the moles of [tex]Cu[/tex].
The balanced chemical reaction will be,
[tex]2Cu_3FeS_3+7O_2\rightarrow 6Cu+2FeO+6SO_2[/tex]
From the balanced reaction, we conclude that
As, 2 moles of [tex]Cu_3FeS_3[/tex] react to give 6 moles of [tex]Cu[/tex]
So, 7295.48 moles of [tex]Cu_3FeS_3[/tex] react to give [tex]\frac{6}{2}\times 7295.48=21886.44[/tex] moles of [tex]Cu[/tex]
Now we have to calculate the mass of [tex]Cu[/tex]
[tex]\text{Mass of }Cu=\text{Moles of }Cu\times \text{Molar mass of }Cu[/tex]
[tex]\text{Mass of }Cu=(21886.44mole)\times (63.546g/mole)=1390795.716g[/tex]
The theoretical yield of [tex]Cu[/tex] = 1390795.716 g
The actual yield of [tex]Cu[/tex] = ?
Now we have to calculate the actual yield of [tex]Cu[/tex].
[tex]\%\text{ yield of }Cu=\frac{\text{Actual yield of }Cu}{\text{Theoretical yield of }Cu}\times 100[/tex]
[tex]86.3=\frac{\text{Actual yield of }Cu}{1390795.716g}\times 100[/tex]
[tex]\text{Actual yield of }Cu=1200256.703g=1.20\times 10^6g=1.20\text{ metric ton}[/tex]
Therefore, the mass of copper produced is, [tex]1.20\text{ metric ton}[/tex]
