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Gina hit a softball 3/4 of the way to the fence in right field. Pete hit a ball half as far as Gina. Erich hit a ball halfway between Gina’s and Pete’s balls. How far did Erich’s ball go?

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TaeKwonDoIsDead

Answer:

[tex]\frac{9}{16}[/tex]  of the way

Step-by-step explanation:

Pete hit half as far as gina, that would be  [tex]\frac{1}{2}*\frac{3}{4}=\frac{3}{8}[/tex]

Since gina hit 3/4 and pete hit 3/8, to find Erich, we add the two and divide by 2 (average) to get Erich's distance:

[tex]\frac{\frac{3}{4}+\frac{3}{8}}{2}=\frac{9}{16}[/tex]

So, Erich's ball went 9/16th of the way

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