Respuesta :
Answer:Following is the program for the count of negative integers in an array:-
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,count=0;//declaring 2 variables n and count and initializing count with 0..
cout<<"Enter the size of the array"<<endl;
cin>>n;//prompting the size of the array...
int negative_nums[n];//array of integers of size n..
cout<<"Enter the numbers"<<endl;
for(int i=0;i<n;i++)
cin>>negative_nums[i];//prompting elements of the array...
for(int i=0;i<n;i++)//iterating over the array....
{
if(negative_nums[i]<0)// if integer in the array at ith position is negative...
count++;// increasing the count...
}
cout<<"The number of negative numbers are "<<count<<endl;//printing the count of negative integers...
return 0;
}
Explanation:
1. In the program i have taken a count integer initializing it with 0
2. Iterating over the array.
3. If the element at ith position is less than zero then increasing the count by 1.
4.Printing the count of negative integers in the array.
