Answer:[tex]4.802 m/s^2[/tex]
Explanation:
height of slope(h) =90 foot
[tex]\theta =40[/tex]
weight of snowboarder=170 pounds\approx 77.1107 kg
[tex]\mu =0.2[/tex]
as the snowboarder is sliding down the slope therefore
Now net acceleration of snowboarder is
[tex]a_{net}=gsin\theta -\mu \cdot gcos\theta[/tex]
[tex]a_{net }=9.81\times sin\left ( 40\right )-0.2\times 9.81\times cos\left ( 40\right )[/tex]
[tex]a_{net }=4.802 m/s^2[/tex]
