Answer:
[tex]\dot{W} = 339.84 W[/tex]
Explanation:
given data:
flow Q = 9 m^{3}/s
velocity = 8 m/s
density of air = 1.18 kg/m^{3}
minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as
[tex]\dot{W} =\dot{m}\frac{V^{2}}{2}[/tex]
here [tex]\dot{m}[/tex]is mass flow rate and given as
[tex]\dot{m} = \rho*Q[/tex]
[tex]\dot{W} =\rho*Q\frac{V^{2}}{2}[/tex]
Putting all value to get minimum power
[tex]\dot{W} =1.18*9*\frac{8^{2}}{2}[/tex]
[tex]\dot{W} = 339.84 W[/tex]
