Answer:
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the slope m = 3 and the point P(10, -9).
Pu the value of slope and the coordinates of the point (x = 10, y = -9) to the equation of a line:
[tex]-9=3(10)+b[/tex]
[tex]-9=30+b[/tex] subtract 30 from both sides
[tex]-39=b\to b=-39[/tex]
Finally:
[tex]y=3x-39[/tex]