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8) A mixture of He, Ne and Ar has a pressure of 7.85 atm. If the Ne has a mole fraction of 0.47 and 8) Ar has a mole fraction of 0.23, what is the pressure of He? A) 4.2 atm B) 3.7 atm C) 5.5 atm D) 2.4 atm E) 1.8 atm

Respuesta :

Answer: The correct answer is Option D.

Explanation:

To calculate the pressure of the Helium gas, we use the equation:

[tex]p_i=\chi \times P[/tex]

where,

[tex]p_i[/tex] = partial pressure of the gas

[tex]\chi[/tex] = mole fraction of the gas

P = total pressure

We are given:

Sum of all the mole fraction is always equal to 1.

[tex]\chi_{Ne}=0.47\\\chi_{Ar}=0.23\\\chi_{He}=(1-(0.47+0.23))=0.3\\P=7.85atm[/tex]

Putting values in above equation, we get:

[tex]p_i=0.3\times 7.85=2.4atm[/tex]

Hence, the correct answer is Option D.

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