For this case we have by definition, that the equation of a line in the slope-intersection form is given by:
[tex]y = mx+b[/tex]
Where:
m: It's the slope
b: It is the cutoff point with the y axis
We need two points through which the line passes to find the slope:
[tex](0,1)\\(1, -2)[/tex]
We found the slope:
[tex]m = \frac {y2-y1} {x2-x1}\\m = \frac {-2-1} {1-0} = \frac {-3} {1} = - 3[/tex]
So, the equation is of the form:
[tex]y = -3x + b[/tex]
We substitute a point to find "b":
[tex]1 = -3 (0) + b\\1 = b[/tex]
Finally, the equation is:
[tex]y = -3x+1[/tex]
Answer:
Option C
