Answer:
2.67 N/kg
Explanation:
We are given that an object that weighing 75 N is pulled on a horizontal surface by a horizontal pull of 50 N to the right with 30 N friction to the left.
We are to find the acceleration of the object.
Mass = 75/10 = 7.5 kg
Acceleration = Net Force / mass
Net force = Horizontal force - Frictional force = 50 - 30 = 20
Acceleration of the object = 20 / 7.5 = 2.67 N/kg
Answer:
[tex]2.61m/s^2[/tex]
Explanation:
We first of all find the net force F acting on the object. The frictional force [tex]F_f[/tex] and the pulling force [tex]F_p[/tex] act in opposite directions. Hence the net force is given as follows;
[tex]F=F_p-F_f...............(1)\\Given;\\F_p=50N\\F_f=30N\\Hence;\\F=50-30\\F=20N[/tex]
It is this net force that brings about the acceleration of the body. Recall that
[tex]F=ma..............(2)[/tex]
where m is the mass of the object and a is the acceleration.
The weight W of the object is given, hence we obtain its mass as follows;
[tex]W=mg..............(3)[/tex]
where g is acceleration due to gravity taken as [tex]9.8m/s^2[/tex].
Given;
W = 75N
[tex]75=m*9.8\\m=\frac{75}{9.8}\\m=7.65kg[/tex]
From equation (2), we have
[tex]a=\frac{F}{m}..................(4)[/tex]
Hence;
[tex]a=\frac{20}{7.65}\\a=2.61m/s^2[/tex]
