Please help!!!!!!!!!!

Answer:
1.
[tex]\dfrac{1}{2}at^2=vt-d[/tex]
2.
[tex]at^2=2(vt-d)[/tex]
3.
[tex]a=\dfrac{2(vt-d)}{t^2}.[/tex]
Step-by-step explanation:
First, express from the formula [tex]d=vt-\dfrac{1}{2}at^2[/tex] the term [tex]\dfrac{1}{2}at^2:[/tex]
[tex]\dfrac{1}{2}at^2=vt-d[/tex]
Now multiply this equation by 2:
[tex]at^2=2(vt-d)[/tex]
and divide it by [tex]t^2:[/tex]
[tex]a=\dfrac{2(vt-d)}{t^2}.[/tex]