Answer:
0.237 (23.7 %)
Explanation:
The thermal efficiency of an engine is given by:
[tex]\eta=\frac{W}{Q_{in}}[/tex]
where
W is the useful work output of the engine
[tex]Q_{in}[/tex] is the heat in input
Here we have:
[tex]Q_{in}=1940 J[/tex]
and the work done is the total heat in input minus the heat exhausted:
[tex]W=1940 J - 1480 J=460 J[/tex]
So, the efficiency is
[tex]\eta=\frac{460 J}{1940 J}=0.237[/tex] (23.7 %)
