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A body of mass 10kg and initially at rest is subjected to a force of 20N for 1 second.calculate the kinetic energy during that time​

Respuesta :

MathPhys

Answer:

20 J

Explanation:

First find the acceleration:

F = ma

20 N = (10 kg) a

a = 2 m/s²

Now find the final velocity:

v = at + v₀

v = (2 m/s²) (1 s) + 0 m/s

v = 2 m/s

Now find the final kinetic energy:

KE = 1/2 mv²

KE = 1/2 (10 kg) (2 m/s)²

KE = 20 J

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