Answer:
next step is to take
- [tex]\frac{b^{2}-4ac }{4a^{2} }[/tex] to the other side
ie: [tex](x+\frac{b}{2a} )^{2}[/tex] = [tex]\frac{b^{2}-4ac }{4a^{2} }[/tex]
now take the square to the other side it will become a root
x + [tex]\frac{b}{2a}[/tex] =± [tex]\sqrt\frac{b^{2} -4ac}{4a^{2} }[/tex]
now take the fraction
x = [tex]\frac{-b}{2a}[/tex] ± [tex]\sqrt\frac{b^{2}-4ac }{4a^{2} }[/tex]
simplify [tex]\sqrt\frac{b^{2}-4ac }{4a^{2} }[/tex]
you will get ± [tex]\sqrt{b^{2}-4ac }[/tex] / 2a
next is you subtract -[tex]\frac{b}{2a}[/tex] and rewrite radical
which will give you
x = -b ± [tex]\sqrt{b^{2}-4ac }[/tex] /2a
HOPE THIS HELPED
