Answer:
h(t) = 56*t - 16.1*t^2
Step-by-step explanation:
The general quadratic formula for these cases is
h(t) = h0 + v*t + 0.5*a*t^2
Where
a = the acceleration of the body. In this case, since the rocket is going upwards, we take the acceleration of the gravity.
a = -32.2 feet/s^2 = -9.8 m/s^2
v = the velocity
v = 56 ft/s
h0 = the initial distance. Since it launched from ground
h0 = 0
h(t) = 56*t - 16.1*t^2
See, attached picture
